Math, asked by jsmnhssn9, 9 months ago

if x%of 1/y =16 2/3% of 1/150 then what percent of y is x​

Answers

Answered by pulakmath007
6

SOLUTION

GIVEN

 \displaystyle \sf{x \% \: \:  \:  of \:  \:  \:  \frac{1}{y}  = 16 \frac{2}{3} \% \:  \:  \: of  \: \:  \frac{1}{50}  }

TO DETERMINE

The percentage of y is x

EVALUATION

Here it is given that

 \displaystyle \sf{x \% \: \:  \:  of \:  \:  \:  \frac{1}{y}  = 16 \frac{2}{3} \% \:  \:  \: of  \: \:  \frac{1}{50}  }

 \displaystyle \sf{ \implies  \frac{1}{y}  \times  \frac{x}{100}  = \frac{1}{50} \times  \frac{ \frac{50}{3} }{100}   }

 \displaystyle \sf{ \implies  \frac{x}{y}    = \frac{1}{50} \times   \frac{50}{3}    }

 \displaystyle \sf{ \implies  \frac{x}{y}    =   \frac{1}{3}    }

Let x is r% of y

 \displaystyle \sf{ \implies \: y \times  \frac{r}{100}   = x  }

 \displaystyle \sf{ \implies \:   \frac{r}{100}   =  \frac{x}{y}   }

 \displaystyle \sf{ \implies \:   \frac{r}{100}   =  \frac{1}{3}   }

 \displaystyle \sf{ \implies \:   r   =  \frac{100}{3}   }

 \displaystyle \sf{ \implies \:   r   =  33\frac{1}{3}   }

So the required percentage

 \displaystyle \sf{ = 33 \frac{1}{3}   \% }

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Answered by kumarishyalu6
1

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