if x % of y 1/y = 162/3 % of 1/150 then what % of y is x
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Given equation is:
9ax+12ay=63
In question given x=1,y=1
Putting x and y values in equation
⇒9a(1)+12a(1)=63
⇒9a+12a=63
⇒21a=63
⇒a=3
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