Math, asked by Configuration, 1 year ago

If x% of y is equal to 1 % of z, y % of z is equal to 1 % of x and z% of x is equal to 1% of y, then the value of xy + yz + zx is equal to?

Answers

Answered by snehitha2
30
x% of y is equal to 1% of z

x/100×y = 1/100 × z

xy/100 = z/100

xy = z -----(1)

y % of z is equal to 1 % of x

y/100 × z = 1/100 × x

yz/100 = x/100

yz = x ------(2)

z% of x is equal to 1% of y

z/100 × x = 1/100 × y

xz/100 = y/100

xz = y ------(3)

We need to find the value of xy+yz+xz

→ y + x + z

→ x + y + z

Hope it helps...

Configuration: But the options that were given in my question paper were 1 , 2 , 3 and 4. Which one of them shud be the answer?
Answered by anurag564660
49

Answer:

x/100×y = 1/100 × z

xy/100 = z/100

xy = z -----(1)

y % of z is equal to 1 % of x

y/100 × z = 1/100 × x

yz/100 = x/100

yz = x ------(2)

z% of x is equal to 1% of y

z/100 × x = 1/100 × y

xz/100 = y/100

xz = y ------(3)

We need to find the value of xy+yz+xz

→ y + x + z

→ x + y + z

The answer is 3 for the above question.

xy = z

Putting y = xz in above equation:

x^2 z = z

x^2 = 1

x = plus minus 1

but x should be equal to +1, since it doesn't satisfies the above equations.

Therefore, x + y + z = 3.

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