Question

if x% of y is equals to1%of z and y% of z equals to 1% of x and z% of x is equals to 1% of y then find the value of xy+yz+zx.​

Answer 1

x/100 x y = 1/100 ×

z

xy/100 = z/100

xy = Z -----(1)

y % of z is equal to 1% of x

y/100 x z = 1/100 x x

yz/100 = x/100

yz = x ------(2)

z% of x is equal to 1% of y

z/100 x x = 1/100 x y

z/100 x = 1/100 x y

xz/100 = y/100

xz = y -(3)

We need to find the value of xy+yz+XZ

+ y

+ x + z

- x + y +z

The answer is 3 for the above question.

xy = z

Putting y = xz in above equation:

x^2 z = z

x^2 = 1

x = plus minus 1

but x should be equal to +1, since it doesn't

satisfies the above equations.

Therefore, x + y + z = 3.