if x = p + 1/p , y = p - 1/p. Find x⁴-2x²y² + y ⁴
Answers
Answered by
6
(p + 1/p)^2 = p^2 + 1/p^2 +2 = x^2
(p - 1/p)^2= p^2 + 1/p^2 - 2 = y^2
Now
x⁴-2x²y² + y ⁴
(x^2 - y^2)^2
so
( p^2 + 1/p^2+2 - p^2 -q^2 +2)^2
4^2
16
Answered by
9
Step-by-step explanation:
x4-2×2y2+y4
(×^2-^)^2
so
(p^2+1/p^2+2-q^2-p^2+2)^2
4×2
=16
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