Question

If x=p+1,y=p+2,z=p+3 then find x^3+y^3+z^3-3xyz?

Answer 1

Answer:

When we replace the value of x,y,z then we get the equation

p^3+3p^2+3p+1+p^3+6p^2+12p+8+p^3+9p^2+27p+27-3p^3-9p^2-9p^2-27p-6p-18

42p+36-33p-18

9p+18