If x=p+1,y=p+2,z=p+3 then find x^3+y^3+z^3-3xyz?
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When we replace the value of x,y,z then we get the equation
p^3+3p^2+3p+1+p^3+6p^2+12p+8+p^3+9p^2+27p+27-3p^3-9p^2-9p^2-27p-6p-18
42p+36-33p-18
9p+18
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