Question

If (x-p)^2+(y-q)^2=0 then find value of (x+p)^2+ (y+q)^2​

Answer 1

Hint :

You got p=cy2. Put this in the given equation and find the value of q. Then use dz=pdx+qdy and hence solve it.

Finally get ,

dz=cy2dx+c2−2y3z−2cxy2y4dy.

⟹2(ydz+zdy)=c2y3dy+2cydx−xdyy2

⟹2d(zy)=c2y3dy+2cd(x/y)

⟹2zy=−c22y2+2c.xy+c1