Question

if x+p is a factor of p(x)=x^5-p^2x^3+44x-48.

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Show step by step solution
Class IX​
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Answer 1

Step-by-step explanation:if x+p is a factor then it is equal to 0

x+p=0

x=-p

put -p in place of 'x' in equation

x^5-p^2x^3+44x-48

(-p)^5-p^2(-p)^3+44(-p)-48

(-p)^5+p^5-44p-48

-44p=48

p=-12/11

Answer 2

The given question is

${x}^{5} - {p}^{2} {x}^{3} + 44x - 48$

if x+p is a factor, then x=-p

sub x=-p in the equation.

$p( - p) = { - p}^{5} - {p}^{2} {( - p)}^{3} + 44( - p) - 48 \\ = - {p}^{5} + {p}^{5} - 44p - 48$

cancel the like terms then we get

$= - 44p - 48 \\ 44p = - 48 \\ p = \frac{ - 48}{ 44} \\ p = - \frac{12}{11}$

Therefore, the final answer is

$\frac{ - 12}{11}$

# spj2

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