Question

If X - P (m) and its coefficient of variation is 50. what is the probability
assume only non-zero values?

(a) 0.018.
(b) 0.982.
(c) 0.989
(d) 0.976,
​

Answer 1

Answer:

b.0.982

Step-by-step explanation:

We are given that

$X\sim P(m)$

COV=50.

We have to find the probability assume only non- zero values.

$COV=\frac{SD}{mean}\times 100$

Let mean=m , variance=m

Then, $SD=\sqrt m$

Substitute the values

Then, we get

$50=\frac{\sqrt m}{m}\times 100$

$\sqrt m=2$

$m=(2)^2=4$

In Poisson distribution

$P(X=x)=\frac{e^{-m}\cdot m^X}{X!}$

$P(X> 0)=1-P(X=0)$

$P(X>0)=1-\frac{e^{-4}\cdot 4^0}{0!}$

$P(X>0)=1-\frac{1}{e^4}=1-0.01832=0.98168$

$p(X >0)=0.982$

Answer:b.0.982