Question

If x = √p+q + √p-q/√p+q - √p-q,then find the value of qx^2-2px+q

Answer 1

$x=\frac{\sqrt{p+q}+\sqrt{p-q}}{\sqrt{p+q}-\sqrt{p-q}}\\\\rationalize\\\\x=\frac{\sqrt{p+q}+\sqrt{p-q}}{\sqrt{p+q}-\sqrt{p-q}}*\frac{\sqrt{p+q}+\sqrt{p-q}}{\sqrt{p+q}+\sqrt{p-q}}\\\\=\frac{p+q+p-q+2\sqrt{p^2-q^2}}{p+q-(p-q)}=\frac{p+\sqrt{p^2-q^2}}{q}\\\\obviously,\ x=root\ of\ quadratic:\ qx^2-2px+q\\\\So\ value=0$

Answer 2

Answer:

If x = √(p + q)+√(p - q)√(p + q)-√(p - q) find value of qx^2 - 2px + q

Step-by-step explanation: