If x, p, q, y are in A.P., then the value of p/q is? answer fast please
Answers
Step-by-step explanation:
Given p,q,r are in AP ⟹2q=p+r
Given
px
a−x
=
qy
a−y
=
r
a−z
=k (say)
⟹p=
kx
a
−
k
1
Similarly q=
ky
a
−
k
1
,r=
kz
a
−
k
1
2q=p+r
⟹
ky
2a
−
k
2
=
kx
a
−
k
1
+
kz
a
−
k
1
⟹
k
a
(
y
2
)=
k
a
(
x
1
+
z
1
)
⟹
y
2
=
x
1
+
z
1
⟹x,y,z are in HP
Given :- If x, p, q, y are in A.P., then the value of p/q is ?
Solution :-
given that, x, p, q, y are in A.P.,
so,
→ (p - x) = (q - p) = (y - q) = Let k
then,
→ p - x = k
→ p = k + x
and,
→ q - p = k
→ q = k + p
also,
→ y - q = k
→ q = y - k
then,
→ p / q = (k + x)/(k + p)
or,
→ p / q = (k + x) / (y - k)
[ Note :- here k is a constant term . ]
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