Question

If x=pab/a+b then prove that
(x+pa/x-pa)+(x+pb/x-pb)=2

Answer 1

Answer:

Step-by-step explanation:

("x + pa")/("x - pa") = ("b + a + b")/("b - a - b") = ("2b + a")/"- a";.(i)</p>

<p>Again , x = `"pab"/("a + b") =&gt; "x"/"pb" = "a"/("a + b")`</p>

<p>`("x + ")/("x - ") = ("a + a + b")/("a - a - b") = ("2a + b")/"- b"`& &(ii)</p>

<p>Adding (i) and (ii)</p>

<p>`("x + pa")/("x - pa") + ("x + pb")/("x - pb") = ("2b + a")/"- a" +("2a + b")/"- b" = ("a - 2"b"")/"a"&nbsp; + ("b - 2a")/"b"`</p>

<p>`= (-2"b"^2 + "ab" - 2"a"^2 + "ab")/"ab"`</p>

<p>`= (-2"b"^2 + 2 "ab" - 2"a"^2)/"ab"`</p>

<p>`= (2 ("a"^2 - "b"^2))/"ab"` = 2 = RHS</p>

<p>LHS = RHS</p>

Answer 2

Step-by-step explanation:

I hope u understand the answer