Question

if X Plus 1/x =8 evaluate X2+1/x2​

Answer 1

Answer:

$if \: x + \frac{1}{x} = 8$

square both side

${(x + \frac{1}{x} )}^{2} = {8}^{2}$

${x}^{2} + { \frac{1}{x} }^{2} + 2 \times x \times \frac{1}{x} = 64$

${x}^{2} + {( \frac{1}{x}) }^{2} = 64 - 2$

${x}^{2} + \frac{1}{{x}^{2} } = 62$

Answer 2

Step-by-step explanation:

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