Question

If x plus one upon x is equal to 11 find the value of x square + 1 upon x square

Answer 1

Hey friend,
Here is the answer you were looking for:

Given that,

$x + \frac{1}{x} = 11$

Now,
Squaring both the sides we get,

${(x + \frac{1}{x}) }^{2} = {(11)}^{2}$
Using the identity :

$(a + b)^{2} = {a}^{2} + {b}^{2} + 2ab$

Putting a = x
and b = 1/x

x^2 + (1/x)^2 + 2 × x × 1/x = (11)^2

x^2 + 1/x^2 + 2 = 121

x^2 + 1/x^2 = 121 - 2

x^2 + 1/x^2 = 119

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
☺☺

Answer 2

Step-by-step explanation:

It will definitely help you