Question

if x power 4 + y power 4 =47x square y square then show that log x square +y square/7=logx +logy​

Answer 1

Answer:

x4+y4=47x2y2

add log on both

(x2+y2)2=47x2y2

(a-b)2=a2+b2-2ab

so,(x2+y2)2-2(x2y2)=47x2y2

(X2+Y2)2=47X2Y2+2(X2Y2)

(X2+Y2)2=49X2Y2

x2+Y2=7xy

x2+y2/7=xy

add log on both sides

logx2+logy2/7=logx+logy

Step-by-step explanation: