Question

if x=psecA qtanA and y = ptanA qsecA then prove x2-y2 = p2-q2

Answer 1

Given that, x – y = 7
Squaring both sides, we get
(x – y)2 = (7)2
x2 + y2 – 2xy = 49
Its given that xy = 9, 
x2 + y2 – 2 (9) = 49
x2 + y2 = 49 + 18
x2 + y2 = 67

Answer 2

bhai phir rhs ko bhi aise hi solve karna aur dono = prove ho jayenge