Question

If x=psecant and y=qtangent then

Answer 1

Answer:

\textbf{Vector form of the given plane is}

\bf\vec{r}.(3\vec{i}+4\vec{i}-2\vec{k})=5}

Step-by-step explanation:

\textbf{Concept:}

\text{The equation of any plane ax+by+cz+d=0 can be}

\text{written as in vector form as $\vec{r}.(a\vec{i}+b\vec{j}+c\vec{k})=q$}

\text{That is, $\vec{r}.\vec{n}=q$}

\text{Given plane is 3x+4y-2z=5}

\text{It can be written as}

\bf\vec{r}.(3\vec{i}+4\vec{i}-2\vec{k})=5}

Answer 2

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