Math, asked by gungun6163, 1 month ago

If {x∈R:1≥2x-3≥0} then the value of x is

Answers

Answered by guptapreeti051181
2

Let y=

Let y= x

Let y= x 2

Let y= x 2 +2x+3

Let y= x 2 +2x+3x

Let y= x 2 +2x+3x 2

Let y= x 2 +2x+3x 2 +14x+9

Let y= x 2 +2x+3x 2 +14x+9

Let y= x 2 +2x+3x 2 +14x+9 .

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9⇒(y−1)x

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9⇒(y−1)x 2

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9⇒(y−1)x 2 +2(y−7)x+3y−9=0

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9⇒(y−1)x 2 +2(y−7)x+3y−9=0Since, x is real, so discriminant of above equation will be greater than or equal to 0.

Let y= x 2 +2x+3x 2 +14x+9 .⇒y(x 2 +2x+3)=x 2 +14x+9⇒(y−1)x 2 +2(y−7)x+3y−9=0Since, x is real, so discriminant of above equation will be greater than or equal to 0.D≥0

Answered by LEGENDARYSUMIT01
0

Step-by-step explanation:

In the first step in order to remove -3 in the mid 2 x minus 3 I had added plus 3 in all in the second step I had divided by 2 in all in order to get the value of x

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