Question

if x= r cos tita .sin tita ,y = r cos tita and z= r sin tita then x²+y²+z²=?
​

Answer 1

Answer:

x= r cos tita .sin tita ,y = r cos tita and z= r sin tita

then x²+y²+z²

${r}^{2} ( {cos}^{2}x.{sin}^{2}x + {cos}^{2}x + {sin}^{2}x + 2 {cos}^{2}x .sinx + 2cosx.sinx + 2cosx. {sin}^{2}x)$

${r}^{2} ( {cos}^{2}x.{sin}^{2}x + {(cosx + sinx)}^{2} + 2 {cos}^{2}x .sinx + 2cosx. {sin}^{2}x)$

${r}^{2} ( {cos}^{2}x.{sin}^{2}x + 1 + 2 {cos}^{2}x .sinx + 2cosx. {sin}^{2}x)$