If x = r sin A cos B, y = r sin A sin B and
z = r cos A, then prove that:
x² + y² + z² = r²
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Given:
- x = r sin A cos B
- y = r sin A sin B
- z = r cos A
To prove:
- x²+y²+z²=r²
Proof:
L.H.S.=
>> x²+y²+z²
- Putting values of x, y and z
>> (r sin A cos A)²+(r sin A sin B)²+(r cos A)²
>> r² sin²A cos²B + r² sin²A sin²B + r² cos²A
>> r² sin²A(cos²B + sin² B) + r² cos²A
- But, sin²Ø+cos²Ø=1
>> r² sin²A + r² cos²A
>> r²( sin²A + cos²A)
>> r²
>> R.H.S.
Hence, proved.
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