Question

if x=r,then the solution set of the equation root x+1+root x-1=1 is:
it is very inportan answer it fast with correct answer plz

Answer 1

Answer:

We have root(x+1) + root(x-1) = 1

Squaring both sides we get,

x+1 + 2root(x+1)root(x-1)+ x-1 = 1

=> 2x + 2root(x^2-1) = 1

=> 2root(x^2-1) = 1-2x

Again squaring we get

4(x^2-1) = 1-4x+4x^2

=> 4x = 5

=> x = 5/4