If 'x' Red balls are shifted from bag A to bag C the probability of green ball from Bag C is reduced by 1/12 find the value of X.
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Answer:
x = T²/(12G - T)
Step-by-step explanation:
Let say Bag C has
G Green Balls
& T - Total Balls
Probability of Green Balls = G/T
x Red balls are shifted from bag A to bag C
=> Bag C Total Balls = T + x
Probability = G/(T + x)
G/(T + x) = G/T - 1/12
=> 12G T = 12G ( T + x) - T (T + x)
=> T² + Tx - 12Gx = 0
=> T ² - x(12G - T) = 0
=> x = T²/(12G - T)
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