Math, asked by bidiptobose9984, 5 months ago

If x=root 2 + 1 find (x-1/x)^2

Answers

Answered by vandana70113362
0

Answer:

if x=√2+1

√2+1-1/√2

so √2 cancel by√2 and +1 cancel by -1

and answer is 0

Answered by reetidoshi
1

Answer:

x =  \sqrt{2} + 1 \\ x -  \frac{1}{x}  {}^{2}  \\  \sqrt{2 }  + 1 -  \frac{1}{ \sqrt{2}  + 1}   {}^{2}  \\  \sqrt{2}  + 1 -   \frac{ {1}^{2} }{ { \sqrt{2 { }^{2} }  + 1}^{2} }  \\  \sqrt{2 }  + 1 -  \frac{1}{2 + 1 }  \\   \sqrt{2}  + 1 -  \frac{1}{3 }  \\  \sqrt{2}  + 1 - 1 \div 3 \\  \sqrt{2}  + 0 \div 3 \\  \sqrt{2}  \div 3 \\  \frac{ \sqrt{2} }{3}

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