Question

if x=root 5-2 by root5+ 2 and y=root5 + 2 by root 5- 2, find the value of x square+xy+y square

Answer 1

Answer:

X=√5-√2/√5+√2

=(√5-√2)(√5-√2)/(√5+√2)(√5-√2)

={(√5)²-2.√5.√2+(√2)²}/{(√5)²-(√2)²}

=(5-2√10+2)/(5-2)

=(7-2√10)/3

y=√5+√2/√5-√2

=(√5+√2)(√5+√2)/(√5-√2)(√5+√2)

={(√5)²+2.√5.√2+(√2)²}/{(√5)²-(√2)²}

=(5+2√10+2)/(5-2)

=(7+2√10)/3

Now, x²+xy+y²

=x²+y²+xy

={(x+y)²-2xy}+xy

=(x+y)²-xy

={(7-2√10)/3+(7+2√10)/3}²-{(7-2√10)/3×(7+2√10)/3}

={(7-2√10+7+2√10)/3}²-(7-2√10)/(7+2√10)

=(14/3)²-{(7-2√10)(7-2√10)/(7+2√10)(7-2√10)}

=196/9-(7-2√10)²/{(7)²-(2√10)²}

=196/9-(49-2.7.2√10+40)/(49-40)

=196/9-(9-28√10)/9

=(196-9+28√10)/9

=(187+28√10)/9

Answer 2

Answer:

It was not correct answer

97 रूट 5 was right