Question

if x=-root2 is a zero of p(x)=x2+root2x+k then find the value of k

Answer 1

Answer:

k= -4

Step-by-step explanation:

Let $x^{2} +\sqrt{2} x+k$=0

Putting x=$\sqrt{2}$

∴ (√2)²+√2×√2+k = 0

2+2+k=0

4+k=0

k= -4

Answer 2

Answer:

k=0

Step-by-step explanation:

p(x)=x²+√(2x)+k

p(-√2)=0 (given)

(-√2)²+√2(-√2)+k=0

2-2+k=0

k=0