Question

If x=root3 +root 2÷root3-root2 and y=root3 -root2÷root3 +root2 find the value of xsquare- ysquare,if root6 =2.4

Answer 1

Answer:

The answer is 31+20 root6

Answer 2

x=(√3+√2)/(√3-√2)

y=(√3-√2)/(√3+√ 2)

by rationalizing x=5+2√6

by rationalizing y=5-2√6

xsquare-ysquare=[x+y][x-y]

=10×4√6=40√6