If x=root3+root2 by root3-root2 and y=root3-root2 find x-y
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root3+root2/root3-2 * root3+root2/root3/root2 (Because we are rationalising the denominator.)
= (root3+root2)^2/3-2
=(root3+root2)^2
= a^2 + 2ab + b^2
=3+2root6+2
=5+2root6
Now, let's subtract root3-root2 from 5+2root6.
5+2root6 -(root3-root2)
=5+2root6-root3+root2
Therefore, x-y = 5+2root6-root3+root2.
Hope this helped! :P
= (root3+root2)^2/3-2
=(root3+root2)^2
= a^2 + 2ab + b^2
=3+2root6+2
=5+2root6
Now, let's subtract root3-root2 from 5+2root6.
5+2root6 -(root3-root2)
=5+2root6-root3+root2
Therefore, x-y = 5+2root6-root3+root2.
Hope this helped! :P
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