Question

if x= root3-root2,find the value of : x+1/x​

Answer 1

Answer:

x=√3-√2

x+1/x

√3-√2+1/√3-√2

(√3-√2+1)(√3+√2)/(√3-√2)(√3+√2)

using a²-b²= (a-b)(a+b)

(3+√6-√6-2+√3+√2)/(√3)²-(√2)²

(1+√3+√2)/3-2

(1+√3+√2)/1

1+√3+√2

Answer 2

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