if x= root3-root2,find the value of : x+1/x
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Answer:
x=√3-√2
x+1/x
√3-√2+1/√3-√2
(√3-√2+1)(√3+√2)/(√3-√2)(√3+√2)
using a²-b²= (a-b)(a+b)
(3+√6-√6-2+√3+√2)/(√3)²-(√2)²
(1+√3+√2)/3-2
(1+√3+√2)/1
1+√3+√2
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