Math, asked by ananthmilan97, 8 months ago

if x = route 15 then find the value of [x+1/x]^2

Answers

Answered by aachman68
1

Step-by-step explanation:

X = 4 - √15

x² = 16 + 15 - 8√15 = 31 - 8√15

1/x² = 1/31 - 8√15 = (31+8√15) / 961-960 = 31+8√15

x² + 1/x² = 62

PLEASE MARK BRAINLIEST.....

Answered by PhysicsEverything
3

Answer:

x=√15

(x+1/x) ^2= (√15 + 1/√15)^2

identity: (a+b) ^2=a^2+b^2+2ab

15+1/15+2/√15

226/15 + √15/15

Hope it helps and please mark as brainliest

Similar questions