Question

If X=route3+1/route 3-1,y=routee-1/route 3+1,find the value of x^2+xy-y^2

Answer 1

Answer:

x=(√3+1)/(√3-1),y=(√3-1)/(√3+1)

Step-by-step explanation:

x=(√3+1)/(√3-1)

multiply up and down by (√3+1)

=(√3+1)*(√3+1)/(√3-1)*(√3+1)

x=(3+1+2√3)/(3-1)=(4+2√3)/2=2+√3-----(1)

Similarly y=2-√3-----(2)

x²-y²+xy

=(2+√3)²-(2-√3)²+(2+√3)*(2-√3)

=4+3+4√3-(4+3-4√3)+4-3

=4+3+4√3-4-3+4√3+4-3

=1+8√3