If x=rsinAcosC y=rsinAsinC and z=rcosA prove that r^2 = x^2 +y^2+z^2
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Given, x=rsinAcosC ..equation..1
y=rsinAsinC .....equation 2
z=rcosA .....equation 3
squaring and adding all three equations we get the following
x2 +y2+z2=r2(sin2Acos2C + sin2Asin2C + cos2A)
=r2 {sin2A(cos2C + sin2C) + cos2A}
=r2 {sin2A+ cos2A}
∴x2 +y2+z2=r2
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hope it would be help ful
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