If x's income is 28% more than y's and y's income is 25% more than z's. By what % is x's income more than z's?
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Answer:
Step-by-step explanation:
Let Y's income be 100.
So, X's income = 128.
Also given that,
if Z's income is 100, then Y's income is 125.
Let us follow the unitary method,
When Y's income is 125, then Z's income is 100.
When Y's income is 100, then Z's income is (100*100)/125 = 10000/ 125 = 80
Now when Z's income is 80, then X's income is 128.
So, when Z's income is 100, then X's income = 100*128/80= 160.
So, X's income is 60% more than Z's.
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