If x satisfies x²+2x+25<0 and x+2>0 then x belongs to
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Given : x²+2x+25<0 and x + 2 > 0
To Find : x
Solution:
x²+2x+25<0
=> x²+2x+1 + 24<0
=> ( x + 1)² + 24 < 0
( x + 1)² minimum value is 0
Hence 0 + 24 < 0 is not possible
Hence no value of x exists
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