if x = sec∅+ tan∅, then the value of (x +1/х) is
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x=sec@+tan@
1/x = 1/sec@+tan@
Rationalising the dr then
sec@-tan @/sec^2@-tan^2@
We know sec^2@-tan^2@=1
1/x= sec@- tan @
x+1/x= sec @+tan @+sec@- tan@=2sec@
1/x = 1/sec@+tan@
Rationalising the dr then
sec@-tan @/sec^2@-tan^2@
We know sec^2@-tan^2@=1
1/x= sec@- tan @
x+1/x= sec @+tan @+sec@- tan@=2sec@
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