If x sin^3Ø + y cos^3Ø = sin cos Ø and x sin Ø = y cos Ø, prove that
x^2 + y^2 = 1.
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Answer:
Step-by-step explanation:
Given : x sin3 θ + y cos3 θ = sin θ cos θ
⇒ (x sin θ) sin2 θ + (y cos θ) cos2 θ = sin θ cos θ
⇒ (x sin θ) sin2 θ + (x sin θ) cos2 θ = sin θ cos θ (∵ y cos θ = x sin θ
⇒ x sin θ(sin2 θ + cos2 θ) = sin θ cos θ
⇒ x sin θ = sin θ cos θ
⇒ x = cos θ ….(1)
Again x sin θ = y cos θ
⇒ cos θ sin θ = y cos θ
⇒ y = sin θ ….(2)
Squaring and Adding equation (1) and (2)
x^2 + y^2 = cos^2θ + sin^2θ = 1
x^2 + y^2 = 1
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