If x sin cube theta + Y cos cube theta is equal to my sin theta cos theta and as sin theta is equal to me by cos theta prove that X square + Y square is equal to 1
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X sin cube theta +y cos cube theta =sin theta cos theta and x sin theta - y cos theta=0 . Then xsquare + y square
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one month ago
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xsin3? + ycos3? = sin?cos?
and xsin?=ycos?
Put this value in above equation we get
xsin3? + xsin?cos2? = sin?cos?
xsin?(sin2? + cos2?) = sin?cos?
x=cos?
so y=sin?
hence x2 + y2 = sin2? + cos2? = 1
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