if x sin³ Q + y cos³ Q = sin Q × cos Q and x sin Q = y cos Q, prove that x² + y² = 1
(Board term -1 , 2011 )
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hey... here's ur solution !!
GIVEN,
x sin Q = y cos Q
x = y cos Q / sin Q....................... (1)
and,
x sin³Q + y cos³ Q = sinQ cos Q.............. (2)
Elimating x from equ (1) nd (2)
(y cos Q / sinQ) × sin³ Q + y cos ³ Q = sinQ cosQ
y cos Q sin² Q + y cos³ Q = sinQ cosQ
➡ y cos Q sin²Q + y cos³ Q = sin Q cos Q
➡y cosQ ( sin²Q + cos²Q ) = sinQ cosQ
➡y = sinQ...........................(3)
Substituting this value of y in eq. (3)
x = cosQ............................... (4)
squaring and adding eq. (3) and (4), we get
x² + y² = cos²Q + sin²Q = 1
❇Hence Prove ❇
GIVEN,
x sin Q = y cos Q
x = y cos Q / sin Q....................... (1)
and,
x sin³Q + y cos³ Q = sinQ cos Q.............. (2)
Elimating x from equ (1) nd (2)
(y cos Q / sinQ) × sin³ Q + y cos ³ Q = sinQ cosQ
y cos Q sin² Q + y cos³ Q = sinQ cosQ
➡ y cos Q sin²Q + y cos³ Q = sin Q cos Q
➡y cosQ ( sin²Q + cos²Q ) = sinQ cosQ
➡y = sinQ...........................(3)
Substituting this value of y in eq. (3)
x = cosQ............................... (4)
squaring and adding eq. (3) and (4), we get
x² + y² = cos²Q + sin²Q = 1
❇Hence Prove ❇
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