Question

If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1

Answer 1

Answer:

I provided all 20 to you. okay.

And,

Here is ur answer dear:-

=> xsin³theta + ycos³theta= sintheta×costheta.

=> x.sin³theta + cos²theta.(ycostheta) = sintheta.costheta.

• [use xsintheta= ycostheta in above]

=> xsin³theta+ cos²theta× xsintheta= sintheta×costheta.

=> xsintheta( sin²theta + cos²theta) = sintheta×costheta.

=> xsintheta = sintheta×costheta.

=> x = costheta.

=> so, y = sintheta.

now, we know

=> sin²theta + cos²theta = 1 .

put, sintheta = y .

=> costheta = x .

hence, x² + y² = 1 proved..

Badi mehnat lgi..

Answer 2

Answer:

Here is ur answer dear:-

=> xsin³theta + ycos³theta= sintheta×costheta.

=> x.sin³theta + cos²theta.(ycostheta) = sintheta.costheta.

• [use xsintheta= ycostheta in above]

=> xsin³theta+ cos²theta× xsintheta= sintheta×costheta.

=> xsintheta( sin²theta + cos²theta) = sintheta×costheta.

=> xsintheta = sintheta×costheta.

=> x = costheta.

=> so, y = sintheta.

Hope it is correct

Step-by-step explanation: