Math, asked by prettykitty664, 1 month ago

If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1.

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Answers

Answered by roosey
13

Here is ur answer dear:-=> xsin³theta + ycos³theta= sintheta×costheta.=> x.sin³theta + cos²theta.(ycostheta) = sintheta.costheta.• [use xsintheta= ycostheta in above]=> xsin³theta+ cos²theta× xsintheta= sintheta×costheta. => xsintheta( sin²theta + cos²theta) = sintheta×costheta.=> xsintheta = sintheta×costheta.=> x = costheta.=> so, y = sintheta.now, we know

=> sin²theta + cos²theta = 1 .

=> sin²theta + cos²theta = 1 .put, sintheta = y .

=> sin²theta + cos²theta = 1 .put, sintheta = y .=> costheta = x .

=> sin²theta + cos²theta = 1 .put, sintheta = y .=> costheta = x .hence, x² + y² = 1

r u in 10th?

even me I am in 10th

I hope it helps you Army

Answered by IbrahimJamadar238
1

Answer:

Ello Ello..! Anu akka en madtayidiya ?? Uta aayita ? Stay safe akka ! Saranghae ! ❤ ^_^

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