Question

If x=sq roots of 7-4root7then x^2+1/x^2

Answer 1

Answer:

So,

x=(√7+43–√)  

Now

7+4(√3)=22+2∗2∗3–√+(3–√)2  

=(2+3–√)2  

Hence 7+43–√−−−−−−−√ = 2 +3–√  

So x=2+(√3)  

1/x=1(2+3–√)  

=2−3–√22−3–√2  [ multiplying numerator and denominator by  2+(√3)  ]

=2−3–√4–3  

=2+3–√  

So  1/x=2−3–√  

So  x+1x=(2+3–√)+(2−3–√)=4

Answer 2

Answer:

Step-by-step explanation:

So,

x=(√7+43–√)  

Now

7+4(√3)=22+2∗2∗3–√+(3–√)2  

=(2+3–√)2  

Hence 7+43–√−−−−−−−√ = 2 +3–√  

So x=2+(√3)  

1/x=1(2+3–√)  

=2−3–√22−3–√2  [ multiplying numerator and denominator by  2+(√3)  ]

=2−3–√4–3  

=2+3–√  

So  1/x=2−3–√  

So  x+1x=(2+3–√)+(2−3–√)=4