Question

if X square + 1 by X raised to 2
equal to 5 evaluate X raised to 4 + 1 by X raise to 4

Answer 1

$given \\ \frac{ {x}^{2} + 1}{ {x}^{2} } = 5 \\ = > 1 + \frac{1}{ {x}^{2} } = 5 \\ = > \frac{ 1}{ {x}^{2} } = 4 \\ = > {x}^{2} = \frac{1}{4} \\ now \\ \frac{ {x}^{4} + 1 }{ {x}^{4} } \\ = 1 + \frac{1}{ {x}^{4} } \\ = 1 + ({ \frac{1}{ {x}^{2} } )}^{2} \\ = 1 + 16 \\ = 17$

hope it helps.