if X square + 1 by x square equals to 18 then find out x cube minus one by x cube
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Answer:
x'2+1/x'2= 18
(x-1/x)'2 = x'2+1/x'2-2×x×1/x
(x-1/x)'2= 18-2
x-1/x=√16=4
(x-1/x)'3=x'3-1/x'3-3×x×1/x(x-1/x)
(4)'3=x'3-1/x'3-3×4
64=x'3-1/x'3-12
64+12 = x'3-1/x'3
76= x'3-1/x'3
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