If x square -1 is a factor of ax cube + bx square +cx +d show that a+c =0
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Answered by
9
Answer:
x²-1=0
x²=1
x=√1
x=±1
x=1 or x=-1
p(x)=ax³+bx²+cx+d
p(-1)=a(-1)³+b(-1)²+c(-1)+d
a(-1)+b(1)-c+d=0
-a+b-c+d=0
b+d=a+c
Answered by
0
Answer:
a+c = 0
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