If x square -1 is a factor of ax cube + bx square + d , show that a * c =0
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x² - 1 is a factor of ax³ + bx² + c
x² - 1 = (x+1)(x-1)
Therefore even (x+1) and (x-1) are factors
Taking x + 1 = 0
x = -1
a(-1)³ + b(-1)² + c = 0
-a + b + c = 0___________________________(1)
Taking x - 1 = 0
x = 1
a(1)³ + b(1)² + c = 0
a + b + c = 0______________________________(2)
Adding (1) and (2),
2 ( b+c) = 0
b+c = 0_________________________________(3)
(1)-(3)
-a = 0
a = 0
∴ a*c = 0
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