Question

if X square + 1 upon x square is = 34 find the value of each of the folloeing
1. x cube minus one upon x cube​

Answer 1

Answer:

140√2

Step-by-step explanation:

⇒ x² + 1/x² = 34

       Adding -2 to both sides:

⇒ x² + 1/x² - 2 = 34 - 2

⇒ x² + (1/x)² - 2(x * 1/x) = 32

⇒ (x - 1/x)² = 32

⇒ x - 1/x = √32

         Cube on both sides:

⇒ (x - 1/x)³ = (√32)³

⇒ x³ - 1/x³ - 3(x * 1/x)(x - 1/x) = 32√32

⇒ x³ - 1/x³ - 3(1)(√32) = 32√32

⇒ x³ - 1/x³ = 32√32 + 3√32

⇒ x³ - 1/x³ = 35√32

⇒ x³ - 1/x³ = 35√(4² * 2)

⇒ x² - 1/x² = 140√2

Answer 2

Answer:

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• ${x}^{2} +( \frac{ {1} }{x} {)}^{2}$

• Find the value of each of the following

1. $(x - \frac{1}{x} ) {}^{3}$

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$\sf\tt\large{\red {\underline {\underline{⚘\;Given:}}}}$

• ${x}^{2} +( \frac{ {1} }{x} {)}^{2}$

$\sf\tt\large{\red {\underline {\underline{⚘\;To find:}}}}$

• The value of (x-1/x)^3.

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• Kindly refer the above given attachment for more information.
• and for better understanding.

Hope it helps u mate.

Thank you.