Question

if X square + 1 upon x square is equal to 7 find the value of 2 x square + one upon x square​

Answer 1

Answer:

12+1/1/6=72

Step-by-step explanation:

${x}^{2} + 1 \div {x}^{2} = 7$

$2 \times {x}^{2} + 1 \div {x }^{2} = 14$

$7 {x}^{2} = {x}^{2} + 1$

$7 {x}^{2} - {x}^{2} = 1$

$6 {x}^{2} = 1$

$1 \div 6 = {x}^{2}$

$1 \div \sqrt{6} = x$

put x=1/

$put \: \: x = 1 \div \sqrt{6}$

$= 2 {x}^{2} + 1 \div {x}^{2}$

$= 2 \times {1 \div \sqrt[ \sqrt{6} ]{?} }^{2} + 1 \div {1 \div \sqrt{6} }^{2}$