Question

If x square + 1 upon x square is equal to 79 find x plus one upon x

Answer 1

hey mate here is your answer ✌♥✌

x²+(1/x²)=79

so by using

a²+b²=(a+b)²-2ab

x²+(1/x²)=(X+(1/X))²-2(X)(1/X)

79=(X+(1/X))²-2

(X+(1/X))²=81

X+(1/X)=9

hope it will help you ⛄

mark me brainliest ✌✌✌✌✌

Answer 2

$x+\frac{1}{x}=9$

Step-by-step explanation:

Given : $x^2+\frac{1}{x^2}=79$

To Find : $x+\frac{1}[x}$

Solution:

$x^2+\frac{1}{x^2}=79$

Identity : $(x+y)^2=x^2+y^2+2xy$

So, $(x+y)^2-2xy=x^2+y^2$

$x^2+\frac{1}{x^2}=(x+\frac{1}[x})^2-2x(\frac{1}{x})$

$79=(x+\frac{1}{x})^2-2$

$81=(x+\frac{1}{x})^2$

$\sqrt{81}=(x+\frac{1}{x})$

$9=x+\frac{1}{x}$

Hence $x+\frac{1}{x}=9$

#Learn more:

Factorise (x^2+1/x^2)+18(x+1/x)+79

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