Question

if x square + 1 upon x square is equals to 18. find the value of x minus one upon x

Answer 1

Answer:

$x - \frac{1}{x} = 4$

Step-by-step explanation:

${x}^{2} + \frac{1}{ {x}^{2} } = 18 \\ x - \frac{1}{x} = find \\ {(x - \frac{1}{x} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \times x \times \frac{1}{x} \\ {(x - \frac{1}{x} )}^{2} = 18 - 2 \\ x - \frac{1}{x} = \sqrt{16} \\ x - \frac{1}{x} = 4$