Question

if X square + 1 upon x square is equals to 18 find the value of x cube minus one upon x cube​

Answer 1

Answer:

x² + 1/x² = 18... eq 1

x² + 1/x² = 16 + 2

x² + 1/x² - 2 = 16

( x + 1/x )² = 16

( x + 1/x ) = 4... eq 2

Now, x³-1/x³ is in the form of ( a³- b³)

Using the identity,

( x - 1/x ) ( x² + x² × 1/x² + 1/x²)

( x -1/x ) ( x² + 1 + 1/x²)

From eq 1 and 2

(4) ( 18 +1)

4 × 19 = 76

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