Question

if x square + 1/x^2= 38 then find the value of (x-1/x)

Answer 1

hello!

#Ans
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${x }^{2} + \frac{1}{ {x}^{2} } = 38 \\ \\ x {}^{2} + \frac{1}{ {x}^{2} } - 2 = 38 - 2 \\ \\ its \: formula \: of \: (a - b {)}^{2} \\ \\ now \\ \\ (x - \frac{1}{x} ) {}^{2} = 36 \\ \\ x - \frac{1}{x} = \sqrt{36} \\ \\ x - \frac{1}{x} = 6 \: ans$


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Answer 2

Answer:

Step-by-step explanation: